How many electrons constitute 1c of charge?

Q: How many electrons constitute 1c of charge?

$e=1.6\times10^{-19}\,C\,\,and \,charge \,q=1\,C$ $\therefore number\,of\, elctors\, \,n=\frac{q}{e}$ $n=\frac{1}{1.6\times10^{-19}}$ $n=6.25\times10^{18}$

Question

Accepted Answer

$e=1.6	imes10^{-19}\,C\,\,and \,charge \,q=1\,C$ $	herefore number\,of\, elctors\, \,n=\frac{q}{e}$ $n=\frac{1}{1.6	imes10^{-19}}$ $n=6.25	imes10^{18}$

ELECTRIC CHANGES AND FIELDS