If the wavelength of electromagnetic radiation is doubled, what happens to the energy of photon?

Energy of photon $E \,=\,hc/λ $$\therefore E_{1}/E_{2} = (λ_{2}/λ_{1})$ $E_{2}/E = λ/2λ$ $E_{2}=E/2$Energy is halved.

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Accepted Answer

Energy of photon   $E \,=\,hc/λ $$	herefore E_{1}/E_{2}   =  (λ_{2}/λ_{1})$ $E_{2}/E = λ/2λ$ $E_{2}=E/2$Energy is halved.

ELECTROMAGNETIC WAVES