Ans. No. distance between plates, $d = 1\:cm \:\:= 1\times10^{-2 }$\:\:m
Potential difference between the plates, $V= 3\times10^{6 }$ V
∴Electric field between plates
$E= V/d=\frac{ 3\times10^{6 }} {1\times10^{-2 }} = 3\times10^{8 }$ V/m
This is more than the dielectric strength of air $= 3\times10^{8 }$ V/m. so it is no possible.